Question

Graph the inequality y ≤ |x + 2|. Which point is NOT part of the solution?

(0, 0)
(–1, –2)
(1, 2)
(–1, 2)

Answer 1

Answer: ( -1,2 )

x+2 = 0

x = -2

graph |x| with solid line then move the whole thing left 2 which give you (0,0) to (-2,0)

because it is less than equal to, you shade the part below the V then you can clearly see which point doesn't belong in the shaded part which is the point that is not part of the solution.

Hope it helps. :D

Answer 2

(-1 , 2) Not part of the solution

Explanation:

from the graph:

(0 , 0) in the red part ⇒ it's a solution

(-1 , -2) in the red part ⇒ it's a solution

(1 , 2) in the red part ⇒ it's a solution

(-1 , 2) in the red part ⇒ it's Not a solution