Question

If g^2 -g-6 =0 and g< 0 what is the value of -3g​

Answer 1

Explanation:

g^2 - g - 6 = 0 can be factored as such:

g^2 + 2g - 3g - 6 = 0

g(g + 2) - 3(g + 2) = 0

(g - 3) (g + 2) = 0

g = 3, -2

Because g must be less than 0, 3, a positive number greater than 0, cannot be used to solve "-3g". So instead we use the other solution, -2:

-3(-2) = 6, the value of -3g.

Check:

(-2)^2 - (-2) - 6 = 0

(-2)^2 - (-2) = 6

4 - (-2) = 6

4 + 2 = 6