Question

PLEASE HURRY!! What are the solutions to the system of equations?

Answer 1

(0,6),(-2,0)

Explanation:

The given equation are;

`y=x^2+5x+6`

and

`y=3x+6`

We equate both equations to get;

`x^2+5x+6=3x+6`

Regroup all terms on the left hand side to obtain;

`x^2+5x-3x+6-6=0`

`x^2+2x=0`

Factor;

`x(x+2)=0`

`x=0,x+2=0`

`x=0,x=-2`

We can put the values of x into any of equations preferably the linear equation to get;

`y=3(0)+6=6`, when x=0.

and

`y=3(-2)+6=0`, when x=-2.

The solutions are

(0,6),(-2,0)