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What is your he equation, in point-slope form, of the line that is parallel to the given line and passes through the point the point ( -3, 1)?

What is your he equation, in point-slope form, of the line that is parallel to the-example-1

1 Answer

4 votes

Answer:


\large\boxed{y-1=(3)/(2)(x+3)}

Explanation:

Calculate the slope of given line:

The formula of a slope:


m=(y_2-y_1)/(x_2-x_1)

We have the points from the graph: (-2, -4) and (2, 2).

Subtitute:


m=(2-(-4))/(2-(-2))=(2+4)/(2+2)=(6)/(4)=(3)/(2)

The point-slope form of an equation of a line:


y-y_1=m(x-x_1)

We have the point (-3, 1). Parallel lines have the same slope. Therefore the slope m = 3/2. Substitute:


y-1=(3)/(2)(x-(-3))\\\\y-1=\dfrac{3}{2}(x+3)

User Mehmet Kaplan
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