Question

What is your he equation, in point-slope form, of the line that is parallel to the given line and passes through the point the point ( -3, 1)?

Answer 1

`\large\boxed{y-1=(3)/(2)(x+3)}`

Explanation:

Calculate the slope of given line:

The formula of a slope:

`m=(y_2-y_1)/(x_2-x_1)`

We have the points from the graph: (-2, -4) and (2, 2).

Subtitute:

`m=(2-(-4))/(2-(-2))=(2+4)/(2+2)=(6)/(4)=(3)/(2)`

The point-slope form of an equation of a line:

`y-y_1=m(x-x_1)`

We have the point (-3, 1). Parallel lines have the same slope. Therefore the slope m = 3/2. Substitute:

`y-1=(3)/(2)(x-(-3))\\\\`y-1=\dfrac{3}{2}(x+3)