Question

Consider the balanced chemical reaction below and determine the percent yield for carbon dioxide if 37.4 moles of iron(IIl) oxide yielded 66.8 moles of carbon dioxide

Answer 1

= 59.5%

Step-by-step explanation:

The equation for the reaction is;

Fe2O3 (s) + 3CO (g) => 2Fe (s) + 3CO2 (g)

From the equation coefficients one mole of iron oxide react to form three moles of carbon dioxide gas.

Therefore, the expected yield of carbon dioxide is;

= (37.4 moles Fe2O3)× (3 moles CO2/1 mole Fe2O3)

= 112.2 Moles of CO2

To calculate the percentage yield we use the formula;

Percentage yield = (Actual yield/Expected yield) × 100%

= (66.8 moles CO2/112.2 moles CO2)× 100%

= 59.5%