Question

Calculate the energy of the red light emitted by a neon atom with a wavelength of 703.2 nm.

Answer 1

Energy = 2.83*10^-19 J

Step-by-step explanation:

Given:

Wavelength (λ) emitted by a Neon atom = 703.2 nm

To determine:

Energy (E) of the photon of light

Step-by-step explanation:

Energy (E) pf a photon is related to its wavelength (λ) by the Planck's equation:

`E = (hc)/(\lambda)`

where h = Planck's constant = 6.626*10^-34 Js

c = speed of light = 3*10^8 m/s

`E = (6.626 * 10^(-34)Js* 3*10^(8)m/s )/(703.2*10^(-9) m)=2.83*10^(-19)J`

Answer 2

Answer;

2.826 × 10^-19 Joules

Explanation;

Energy of a wave is given by the formula;

E = hf; where E is the energy, h is the Plank's constant, 6.626 × 10^-34 m²/kg/s and f is the frequency.

But; f = c/λ , where c is the speed of light, 2.998 × 10^8 m/s, and λ is the wavelength 7032 nm.

Therefore;

E = hf = hc/λ

= (6.626 × 10^-34 × 2.998 × 10^8 m/s)/(7.032 × 10^-6 m)

= 2.825 × 10^-19 Joules