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Given 4/ (-2 - 6sin(theta)) What is the distance between the pole and the directrix?

1 Answer

1 vote

Answer:

2/3

Explanation:

For a conic equation of the form ...

r = ed/(1+e·sin(θ))

the eccentricity is represented by e and the distance from the pole to the directrix is represented by d.

Your equation can be rewritten in this form as ...

r = 3·(-2/3)/(1 +3·sin(θ))

This means the directrix is 2/3 units below the pole.

Given 4/ (-2 - 6sin(theta)) What is the distance between the pole and the directrix-example-1
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