Question

Two people decided to race. One of the cars is 10 meters north of the start line 5 seconds into the race. After 15 seconds, the car is 25 meters north of the start line. Calculate the average velocity of the car.

Answer 1

The average velocity of the car is 1.5 m/s

Explanation:

The given parameters are;

The displacement of one of the cars north of the start after 5 seconds = 10 meters

The displacement of the car north of the start after 15 seconds = 25 meters

The average velocity of the cars
`\overline v` is given as follows;

`\overline v = (\Delta x)/(\Delta t)`

Where;

Δx = The change in the displacement of the car = 25 m - 10 m = 15 m

Δt = The corresponding amount of the change in time 15 s - 5 s = 10 s

By substituting the known values of Δx and Δt in the equation for the average velocity of the car,
`\overline v`, we have;

`\overline v = (15 \ m)/(10 \ s) = 1.5 \ m/s`

∴ The average velocity of the car,
`\overline v` = 1.5 m/s