What is the sum of an infinite geometric series if the first term is 156 and the common ratio is 2⁄3? A. 260 B. 468 C. 208 D. 234

asked Feb 14, 2020 140k views

5 votes

What is the sum of an infinite geometric series if the first term is 156 and the common ratio is 2⁄3?

A. 260
B. 468
C. 208
D. 234

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3 votes

Answer:

Explanation:

We have

$a_1=156,\ r=(2)/(3)$

If |r| < 1, then the formula of a sum of an infinite geometric sequence is:

S=(a_1)/(1-r)

Substitute:

$S=(156)/(1-(2)/(3))=(156)/((1)/(3))=156\cdot(3)/(1)=468$

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