Answer:
x=-2 is the removable discontinuity of the function.
Explanation:
Given that
![f(x) = (x^2-4x-12)/(x+2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cj84e4cmzcu2djwrwhmn63h44b6ptl2hac.png)
We have to find the discontinuity of the function.
We find the numerator has got a factor as denominator because
![x^2-4x-12 =(x-6)(x+2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/7slzoxq7upikh4g8arj065hmlbp069s87a.png)
x+2 can be cancelled and the function would be
x-6 if x not equals -2
Thus the function is discontinuous at x=-2
The discontinuity is removable if f(-2) is defined as =-8
Thus x=-2 is a removable discontinuity of the function.