Question

6/a - 4/b = 1 and 9/a - 8/b = 1​

Answer 1

a = 3 ; b = 4

Explanation:

Eqn.1 =
`(6)/(a) - (4)/(b) = 1`

Eqn.2 =
`(9)/(a) - (8)/(b) = 1`

Both the eqns have RHS (Right Hand Side) equal. So,

`(6)/(a) - (4)/(b) = (9)/(a) - (8)/(b)`

`= > (6b - 4a)/(ab) = (9b - 8a)/(ab)`

Cancelling ab from both the denominators of both the sides,

`= > 6b - 4a = 9b - 8a`

`= > 8a - 4a = 9b - 6b`

`= > 4a = 3b`

`= > a = (3b)/(4)`

Putting the value of a in Eqn.1,

`(6)/( (3b)/(4) ) - (4)/(b) = 1`

`= > (24)/(3b) - (4)/(b) = 1`

`= > (8)/(b) - (4)/(b) = 1`

`= > (8 - 4)/(b) = 1`

`= > b = 4`

Putting the value of b in the value of a

`a = (3 * 4)/(4) = 3`