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An arch of balloons is tied to a frame. The frame can be modeled by y= -5/8(x-2)(x-10), where x and u are measured in feet. The x-axis represents the ground. Find the width of the frame at ground level

User Regetskcob
by
4.9k points

2 Answers

1 vote

Answer:

8 feet

Explanation:

An arch of balloons is tied to a frame. The frame can be modeled by y= -5/8(x-2)(x-example-1
User Renato Rodrigues
by
5.6k points
3 votes

Answer:

Width = 8 feet

Explanation:

To solve this equation easily, we can plot the equation provided in a graphing calculator, and fin the points where y = 0

y = -5/8*(x-2)(x-10)

With those points, we subtract the values of x and find the solution of your problem.

Please see the attached graph

Width = x2 - x1

x2 = 10

x1 = 2

Width = 8 feet

An arch of balloons is tied to a frame. The frame can be modeled by y= -5/8(x-2)(x-example-1
User Crowie
by
5.2k points
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