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50 POINTS - A Builder intends placing 7 equally spaced homes on a semicircular plot. If the circle has a diameter of 400 feet, what is the distance between any two adjacent homes

2 Answers

6 votes

Answer:

89.7 ft

Explanation:

User Cornish
by
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3 votes

Answer: 89.7 ft

Explanation:

Find the arc length (s) of the semi-circle. Then divide that length by 7.

s = r · θ where r is the radius and θ is the angle in radians

s = (400 ÷ 2) · π (radius is diameter divided by 2)

= 200π

= 628.3

The length of the arc is 628.3 ft. Divide that by 7 to find the distance between each home.

628.3 ÷ 7 = 89.7

User LNF
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5.6k points