Question

Help please? I don’t know how to do this problem

Answer 1

The slope of the line tangent to
`y=x^3+2` at
`x=c` is
`3c^2`. If
`c=3`, then the slope is
`3\cdot3^2=27`.

Use the point-slope formula to get the equation of the tangent line passing through (3, 29), which we know has slope 27:

`y-29=27(x-3)\implies y=27x-52`