Answer:
![z=11](https://img.qammunity.org/2020/formulas/mathematics/college/j4yva71404sahxfmkfoqhdai7ttbi21sta.png)
Explanation:
The perimeter of a rectangle is found using the formula;
![p=2w+2l](https://img.qammunity.org/2020/formulas/mathematics/college/2a23w9jnajinrqawgnch8z1ypnekq5sy5y.png)
The width of the rectangle is
.
The length of the rectangle is
![l=4z](https://img.qammunity.org/2020/formulas/mathematics/college/u9k3aue4u2m71wnz2i04o7xcjaekiglm6z.png)
The perimeter of the rectangle is
![p=158](https://img.qammunity.org/2020/formulas/mathematics/college/m3b7aojsowdznvei2n6dfma63dv0zjbe88.png)
We substitute the given values to obtain;
![158=2(3z+2)+2(4z)](https://img.qammunity.org/2020/formulas/mathematics/college/sv26nzsohhm5vftcqbi73ngdbfxcqod0lr.png)
Expand to obtain;
![158=6z+4+8z](https://img.qammunity.org/2020/formulas/mathematics/college/gzoftf18fdfjp89ogmobai9cfhhlsx2vqe.png)
Group similar terms to get;
![158-4=6z+8z](https://img.qammunity.org/2020/formulas/mathematics/college/bysjloqcqme51et87pb319ckcfqtyjb6ff.png)
Simplify;
![154=14z](https://img.qammunity.org/2020/formulas/mathematics/college/qqs03z6y7urohstgfqx3baszzcjc2q4nw7.png)
![z=11](https://img.qammunity.org/2020/formulas/mathematics/college/j4yva71404sahxfmkfoqhdai7ttbi21sta.png)