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Help please thank you

Help please thank you-example-1
User Gevious
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1 Answer

2 votes

Answer:

Explanation:

Left hand column

-780 works. The arm swings around the origin like a clock twice which makes - 720. You have - 60 left over so that one works.

- 420 works. The clock hand swings around the origin once clockwise. The arm still has -60 to go . - 60 is what you want.

300 will wind up in the same place as - 60. Both are in the 4th quad in the same place.

660 will do the same thing as 300. 660 - 360 = 300. Both 300 and -60 have same terminal arm.

-1020 looks like it works, but it does not. The clock hand swings around the origin twice. That's - 720. You still have - 300 to go. That puts you in the 1st quadrant not the 4th.

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Right hand column

You have to be careful with this one. The reasoning is just slightly different.

145 degrees is in the second quadrant. If you have - 215, the arm will wind up in the same place as 145 (in the second quadrant). What you are looking for is something that is either 145 or - 215

-575 = one revolution around (360) with a remainder of -215 so this one works.

-215 works. See introductory statement for this problem.

505 works. 505 - 360 = 145. The arm swings around the +x axis once and the remainder is 145.

865 works. The terminal arm swings around the + axis twice and gives 865 - 2*360 = 865 - 720 = 145.

User Patrice
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