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5 votes
How do you solve this?

How do you solve this?-example-1

2 Answers

2 votes

Answer:

P = 24 cm

q = 20.7846 cm

Explanation:

Answer:

Sides:

a = 12 cm

b = 24 cm

c = 20.7846 cm

Angles:

A = 30 °

B = 90 °

C = 60 °

Other:

P = 56.7846 cm

s = 28.3923 cm

K = 124.708 cm²

r = 4.3923 cm

R = 12 cm

Agenda:

A = angle A

B = angle B

C = angle C

a = side a

b = side b

c = side c

P = perimeter

s = semi-perimeter

K = area

r = radius of inscribed circle

R = radius of circumscribed circle

Given the size of 2 angles and 1 side opposite one of the given angles, you can calculate the sizes of the remaining 1 angle and 2 sides.

use the Sum of Angles Rule to find the other angle, then use The Law of Sines to solve for each of the other two sides.

User Litwos
by
5.1k points
4 votes

Answer:

  • q = 12√3
  • p = 24

Explanation:

The ratios of side lengths, shortest to longest, in a 30°, 60°, 90° triangle are ...

1 : √3 : 2

Since your shortest side is 12, the other two sides are ...

12 : q : p = 12 : 12√3 : 24

q = 12√3

p = 24

_____

Alternate solution

You can also solve this using trig ratios, as described for you in answer to one of your other questions.

12/q = tan(30°) . . . . q = 12/tan(30°) = 12√3

12/p = sin(30°) . . . . p = 12/sin(30°) = 24

User Willy Pt
by
6.0k points