Answer: The correct option is (C) 5.
Step-by-step explanation: Given that a group of distinct objects can be arranged in 120 different ways.
We are to find the number of objects in the group.
We know that a group of n distinct objects can be arranged in n! ways.
And, for a non-negative integer n, the factorial of n is defined as
![n!=n(n-1)(n-2)~~.~~.~~.~~3.2.1](https://img.qammunity.org/2020/formulas/mathematics/high-school/t7hyjqjmio66ed3rkbcwqhwtlhmorhkbbx.png)
Option (A) : If n = 3, then
![n!=3!=3*2* 1=6\\eq 120.](https://img.qammunity.org/2020/formulas/mathematics/high-school/8kdfyurbl6wi6k4adcw4yvnsuuwpvc9kym.png)
So, option (A) is incorrect.
Option (B) : If n = 4, then
![n!=4!=4* 3*2* 1=24\\eq 120.](https://img.qammunity.org/2020/formulas/mathematics/high-school/fst16a53ye9zilaxubtdirpajnrhwjb3nj.png)
So, option (B) is incorrect.
Option (C) : If n = 5, then
![n!=5!=5*4*3*2* 1=120.](https://img.qammunity.org/2020/formulas/mathematics/high-school/rc9aoi75aokk8fv5mswth0fhgevkk12cv4.png)
So, option (C) is correct.
Option (D) : If n = 6, then
![n!=6!=6*5* 4*3*2*1=720\\eq 120.](https://img.qammunity.org/2020/formulas/mathematics/high-school/bubwre5q8v1s5kwj05lpnxx71tksj3kdjc.png)
So, option (D) is incorrect.
Thus, (C) is the correct option.