Question

I needs help pleaseee

Answer 1

use the pythagorean theorem to find the missing part of A

`{8}a^(2) + {b}^(2) = {10}^(2)`


`64 + {b}^(2) = 100`

remove 64 on both sides

64-64+b^2=100-64

b^2=36

find the square root for 36


`\sqrt{{b}^(2) } = √(36)`

b=6

remember that for later

use Pythagorean theorem again to find the missing side for B


`{a}^(2) + {8}^(2) = {17}^(2)`


`{a}^(2) + 64 = 289`

remove 64 both sides

a^2+64-64=289-64

a^2=225

find square root for 225


`\sqrt {a}^(2) = √(225)`

a=15

add the sides together

6 (b) + 15 (a) = 21