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Complete the square to determine the maximum or minimum value of the function defined by the expression. x2 + 8x + 6

User Justinvf
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1 Answer

2 votes

Answer:

Minimum at (-4, -10)

Explanation:

x² + 8x + 6

The coefficient of x² is positive, so the parabola opens upward, and the vertex is a minimum.

Subtract the constant from each side

x² + 8x = -6

Square half the coefficient of x

(8/2)² = 4² = 16

Add it to each side of the equation

x² + 8x + 16 = 10

Write the left-hand side as the square of a binomial

(x + 4)² = 10

Subtract 10 from each side of the equation

(x+ 4)² -10 = 0

This is the vertex form of the parabola:

(x - h)² + k = 0,

where (h, k) is the vertex.

h = -4 and k = -10, so the vertex is at (-4, -10).

The Figure below shows your parabola with a minimum at (-4, -10).

Complete the square to determine the maximum or minimum value of the function defined-example-1
User Florian Shena
by
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