Factor completely 3bx^2 - 9x^3 - b + 3x

asked Mar 19, 2020 139k views

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Factor out the common terms in the first two terms, then in the last two terms;

3x^2(b - 3x) - (b - 3x)

Factor out the common term b - 3x

= (b - 3x)(3x^2 - 1)

Jacob Hulse answered Mar 25, 2020

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