Question

What are the critical points for the inequality x^2-9x/x-5 < 0?

Answer 1

the critical points are 0,5,9

Explanation:

Answer 2

0, 5 and 9

Explanation:

The critical points for any inequality are the points for which the numerator of the denominator equal 0.

Here, we are given the following inequality:

`\frac { x^2 - 9x } { x - 5 } < 0`

So the critical points will be where
`x^2 - 9x = 0` and where
`x - 5 = 0`.

`x^2 - 9x = 0`

`x (x - 9) = 0`

`x = 0 and x = 9`

`x - 5 = 0`

`x = 5`

Therefore, the critical points for the given inequality are 0, 5 and 9.