Question

The volume V of a given mass of a gas varies directly as a temperature T and inversely as the pressure P. If V=231cm^3 when T=300 degrees Kelvin and P=20lb/cm^2, what is the volume when T=484 degrees Kelvin and P=22lb/cm^2?

Answer 1

V = 338.8
`cm^3`

Explanation:

Basically manipulate the ideal gas law.

PV = nRT

We know n and R are constant so we can cross that out. We get:

PV = T or
`(PV)/(T)`

Let's plug in the values to get:

`(20*231)/(300) =(22*V)/(484)`

We simplify them to get:

`(4620)/(300) =(22V)/(484)`

We cross multiply:

`4620*484 = 300*22V`

Simplify:

`2,236,080 = 6,600V`

Solve for V by dividing both sides by 6,600.

Hope it helps! (: