Question

What are the roots of the polynomial equation? x2−12x−64=0 Enter your answers in the boxes. x= or x=

Answer 1

Here is your answer

`{x}^(2)-12x-64=0`

`{x}^(2)-16x+4x-64=0`

`x(x-16)+4(x-16)=0`

`(x-16)(x+4)=0`

So,

x-16=0 or x+4=0

`<b>x=16 or x=-4</b>`

HOPE IT IS USEFUL

Answer 2

`\bold{ANSWER}`

On solving the following quadratic equation ,

`{x}^(2) - 12x - 64 = 0`

`{x}^(2) - 16x + 12x - 64 = 0`

`x(x - 16) + 12(x - 16) = 0`

`(x + 12)(x - 16) = 0`

so,

x+12 = 0

`\huge \boxed{x = -12}`

x-16 =0

`\huge \boxed{x = 16}`