Question

50POINTS! What is the escape velocity for lunar module? Lunar module mass 15,200 kg radius of moon 1.74x106m, mass of moon 7.34x1022kg

Answer 1

2.73 km/s

Step-by-step explanation:

Answer 2

2.73 km/s

Step-by-step explanation:

The escape velocity of an object in the gravitational field of the moon is (on the surface of the planet)

`v=\sqrt{(2GM)/(r)}`

where

`G=6.67\cdot 10^(-11) m^3 kg^(-1) s^(-2)` is the gravitational constant

`M=7.34\cdot 10^(22) kg` is the mass of the Moon

`r=1.74\cdot 10^6 m` is the radius of the Moon

As we can see, the escape velocity does not depend on the mass of the lunar module.

Substituting the numbers into the formula, we find

`v=\sqrt{(2(6.67\cdot 10^(-11))(7.34\cdot 10^(22)kg))/((1.74\cdot 10^6 m))}=2732 m/s=2.73 km/s`