Question

What is an equation of the line that is parallel to y=9−5x and passes through (0, 8) ?

Enter your equation in the box.

Answer 1

y = 8-5x is equation of line that is parallel to y = 9-5x and passing through (0,8).

Explanation:

We have given a equation of line and a point.

y=9−5x and (x₁,y₁)= (0, 8)

We have to find equation of line that is parallel to given equation of line and passing through given point.

y-y₁ = m(x-x₁) is point-slope form of equation of line where m is slope of line.

Since, we know that parallel line have equal slope of line.

Given equation has slope equal to -5.

Parallel line also has slope equal to -5.

m = -5

Putting values in point-slope form of equation , we have

y-(8) = -5(x-0)

y-8 = -5(x)

y-8= -5x

y = 8-5x is equation of line that is parallel to y = 9-5x and passing through (0,8).

Answer 2

Hello!

The answer is:

`y=8-5x`

Why?

If we want to find an equation of a line parallel to the given line, we must remember that parallel lines has the same slope.

So,

Line equation is:

`y=mx+b`

Where:

`m=LineSlope`

`b=y-axisIntercept`

So, we are given the function:

`y=9-5x`

Where:

m=-5

Also, we are given the point where the line passes through (0,8), we can use it to find "b"

`y=b-5x\\y+5x=b\\b=8+5(0)=8`

So, the equation will be:

`y=8-5x`

To prove if we are right, let's substitute (0,8):

`8=8-5(0)`

`8=8-0`

`8=8`

Have a nice day!