Question

The displacement of a car is a function of time as follows: x(t)=25+3.0t², with x is in meters. Find the average velocity between t1 = 1.0s and t2 = 4.0s.​

Answer 1

Answer: 15m/s

Step-by-step explanation: Average Velocity is vector describing the total displacement of an object and the time taken to change its position. It is represented as:

`v=(\Delta x)/(\Delta t)`

At t₁ = 1.0s, displacement x₁ is:

`x(1)=25+3(1)^(2)`

x(1) = 28

At t₂ = 4.0s:

`x(4)=25+3(4)^(2)`

x(4) = 73

Then, average speed is

`v=(73-28)/(4-1)`

v = 15

The average velocity of a car between t₁ = 1s and t₂ = 4s is 15m/s