Question

Solve the quadratic by factoring.
2x^2+4=-5x+1

Answer 1

x=3/2,1

Explanation:

(Ignore the A's in the equation i couldn't find a way to get rid of them

Example of what im taliking about -
`±` the A ignore this)

Move all terms to the left side of the equation and simplify.

`2x^2-5x+3=0`

Use the quadratic formula to find the solutions.

`\frac{-b±\sqrt[]{b^2-4(ac)} }{2a}`

Substitute the values a=2

, b=−5, and c=3 into the quadratic formula and solve for x

`(5±√(b^2 - 4 (ac)) )/(2a)`

Simplify.

`x=(5±1)/(4)`

The final answer is the combination of both solutions.
`±`

x=32,1
`x= (3)/(2) ,1`

Hopefully this helps ^.^

Answer 2

see explanation

Explanation:

Given

2x² + 4 = - 5x + 1

To express in standard form subtract - 5x + 1 from both sides

2x² + 5x + 3 = 0 ← in standard form

Consider the factors of the product of the x² term and the constant term which sum to give the coefficient of the x- term

product = 2 + 3 = 6 and sum = + 5

The factors are + 2 and + 3

Use these factors to split the x- term

2x² + 2x + 3x + 3 = 0 ( factor the first/second and third/fourth terms )

2x(x + 1) + 3(x + 1) = 0 ← factor out (x + 1)

(x + 1)(2x + 3) = 0

Equate each factor to zero and solve for x

x + 1 = 0 ⇒ x = - 1

2x + 3 = 0 ⇒ 2x = - 3 ⇒ x = -
`(3)/(2)`