Question

What is the sine of angle x ?

Answer 1

Hello!

The answer is:
`sin(x)=(b)/(c)`

Why?

Since it's a right triangle, we can determine the Sine of the angle "x" using the following formula:

`sin(x)=(b)/(c)`

Where:

`b=opposite\\a=hypotenuse`

Also, we can determine the cosine and the tangent of the same angle "x" using the following formulas:

`cos(x)=(a)/(c) \\tan(x)=(b)/(a)`

Where:

`a=hypotenuse\\b=opposite\\c=adjacent`

Have a nice day!

Answer 2

Answer:
`sinx=(b)/(c)`

Explanation:

By definition you have that:

`sin\alpha=(opposite)/(hypotenuse)`

Based on the figure attached in the problem you have that:

`\alpha=x\\opposite=b\\hypotenuse=c`

Therefore, you must substitute the above into
`sin\alpha=(opposite)/(hypotenuse)`

Then, the answer is:

`sinx=(b)/(c)`