Answer:
![Length=10.5\ ft](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qow5qtaodddfi8ofcwlqdq3w3tl63t0oee.png)
![Width=10.5\ ft](https://img.qammunity.org/2020/formulas/mathematics/middle-school/z1c2tusvufym5de5dscq1ycjttrey2t0lm.png)
![Area=110.25\ ft^(2)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/9qt0gr3kq929qrtu4nljf0kxm5ez26otze.png)
Explanation:
Let
x----> the length of the rectangular garden
y---> the width of the rectangular garden
we know that
The perimeter of the rectangle is equal to
![P=2(x+y)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/gngxe3s33xysybvyb1kvhl9igkv26xdlmw.png)
we have
![P=42\ ft](https://img.qammunity.org/2020/formulas/mathematics/middle-school/cd68oh41zyhw7pm8a1av5gyu9fd92412wf.png)
so
![42=2(x+y)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/lgbbtpi7su5nznorjnac4hla95jk70dmzb.png)
simplify
![21=(x+y)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/ao8ug6ur38vc1wqsluy7e7wy4tevt9xyll.png)
------> equation A
Remember that the area of rectangle is equal to
----> equation B
substitute equation A in equation B
----> this is a vertical parabola open downward
The vertex is a maximum
The y-coordinate of the vertex is the maximum area
The x-coordinate of the vertex is the length side of the rectangle that maximize the area
using a graphing tool
The vertex is the point
![(10.5,110.25)](https://img.qammunity.org/2020/formulas/mathematics/middle-school/qbvkth1jwp458ktdruw5s6d02z6rd13nia.png)
see the attached figure
so
![x=10.5\ ft](https://img.qammunity.org/2020/formulas/mathematics/middle-school/pzp8hvxbaggs44hgouof9mx7pgxsv62zj7.png)
Find the value of y
![y=21-10.5=10.5\ ft](https://img.qammunity.org/2020/formulas/mathematics/middle-school/soowwfxnd42lnkeyn24xnmqa55xdi6gbm2.png)
The garden is a square
the area is equal to
----> is equal to the y-coordinate of the vertex is correct