Answer:
![125\ ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/qb7kg44t5mnpmd6gmfxj4o93kh07ovh69r.png)
Explanation:
see the attached figure to better understand the problem
step 1
In the right triangle ABC find the length side BC
we know that
![tan(62\°)=(124)/(BC)](https://img.qammunity.org/2020/formulas/mathematics/high-school/qfax80szjctgu3ob6gt9d518aeylwyt3w6.png)
![BC=(124)/(tan(62\°))](https://img.qammunity.org/2020/formulas/mathematics/high-school/d3m2vafyx27zk1olvk4jjblgwzt413szjt.png)
step 2
In the right triangle ABD find the length side BD
we know that
![tan(33\°)=(124)/(BD)](https://img.qammunity.org/2020/formulas/mathematics/high-school/sp20xojr6mk1uy6idlaxn43xjh0ef892rp.png)
![BD=(124)/(tan(33\°))](https://img.qammunity.org/2020/formulas/mathematics/high-school/fwwck8wvujso9dsevg0o5chfzflap22dlh.png)
step 3
we know that
The distance between the two boats is the length side CD
![CD=BD-BC](https://img.qammunity.org/2020/formulas/mathematics/high-school/je23kyimj3f2f1aii8z54nib1uspvyljfu.png)
substitute the values
![CD=(124)/(tan(33\°))-(124)/(tan(62\°))=125\ ft](https://img.qammunity.org/2020/formulas/mathematics/high-school/72ekn3uiqu2d52wcq8w77z3m5f1kvvehks.png)