If p(a) = 2/3, p(b) = 4/5, and p(anb) = 3/5, what is P( AuB) ( the n is the arc shape direction, so is the u)

BuffaloBuffalo asked Mar 23, 2023

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BuffaloBuffalo asked Mar 23, 2023

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22 votes

By the inclusion/exclusion principle,

$P(A\cup B) = P(A) + P(B) - P(A\cap B)$

$P(A\cup B) = \frac23 + \frac45 - \frac35$

$P(A\cup B) = (10)/(15) + (12)/(15) - \frac9{15}$

$P(A\cup B) = \boxed{(11)/(15)}$

Mann answered Mar 29, 2023

by Mann

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