Question

A man in a gym is holding an 8.0-kg object at arm's length, a distance of 0.55 m from his shoulder joint. What is the torque about his shoulder joint due to the object if his arm is held at 30° below the horizontal?

Answer 1

Answer;

37.4 Nm

Step-by-step explanation;

W = Mg

= 8 × 9.81 m/s²

= 78.5 N

Torque = Perpendicular Force × distance

= 78.5 × Cos 30 × 0.55 m

= 37.4 Nm