Question

What distance does electromagnetic radiation travel in 0.45 ps ?

Answer 1

Electromagnetic radiation travels a distance of 0.135 millimeters in 0.45 picoseconds, when using the speed of light in a vacuum to calculate the distance covered.

Step-by-step explanation:

The question seeks to find the distance electromagnetic radiation travels in a given short period, specifically 0.45 picoseconds (ps). To solve this, one must use the fact that electromagnetic radiation travels at the speed of light, which is approximately 3×108 meters per second (m/s) in a vacuum. By multiplying the time by the speed of light, one can find the distance:

• Speed of light (c) = 3×108 m/s
• Time (t) = 0.45 ps = 0.45×10-12 s (since 1 ps = 10-12 s)

The distance (d) traveled by the electromagnetic wave is calculated as d = c × t, which gives:

d = 3×108 m/s × 0.45×10-12 s

d = 135×10-4 meters

d = 0.135 mm

Therefore, electromagnetic radiation travels a distance of 0.135 millimeters in 0.45 picoseconds.

Answer 2

`135 \mu m`

Step-by-step explanation:

The distance traveled by electromagnetic radiation is given by:

`d=vt`

where

v is the speed of the radiation

t is the time elapsed

Electromagnetic radiation travels at the speed of light, which is equal to:

`v=c=3\cdot 10^8 m/s`

The time elapsed in this problem is

`t=0.45 ps=0.45\cdot 10^(-12) s`

Substituting into the equation, we find

`d=(3\cdot 10^8 m/s)(0.45\cdot 10^(-12) s)=1.35\cdot 10^(-4) m`

which corresponds to
`135 \mu m`