Answer:
Vertex of equation is (5,-3).
Explanation:
We have given a quadratic equation in standard form.
y = x²-10x+22
We have to rewrite given equation in vertex form.
y = (x-h)²+k is vertex form of equation where (h,k) is vertex of equation.
We will use method of completing square to solve this.
Adding and subtracting (-5)² to above equation, we have
y = x²-10x+22+(-5)²-(-5)²
y = x²-10x+(-5)²+22-(-5)²
y = (x-5)²+22-25
y = (x-5)²-3
Hence, vertex of equation is (5,-3).