Two positive charges are seperated by 12 cm. The force thatq1 exerts on q2 is 4×10 ^8N. what is this force if the distance between the two charges is reduced to 9cm?

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asked Aug 2, 2020 225k views

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Two positive charges are seperated by 12 cm. The force thatq1 exerts on q2 is 4×10 ^8N. what is this force if the distance between the two charges is reduced to 9cm?

Two positive charges are seperated by 12 cm. The force thatq1 exerts on q2 is 4×10 ^8N-example-1

Physics
middle-school

Alexey Kosov asked

by Alexey Kosov

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The new force is 7.11 x 10^8 N.

Dimitri Merejkowsky answered Aug 5, 2020

by Dimitri Merejkowsky

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