Question

How many grams of copper (I) chloride can be produced from the reaction of 73.5 g of copper (I) oxide with hydrochloric acid according to the following reaction? Cu2O + 2 HCl à 2 CuCl + H2O

Answer 1

To determine the amount of copper (I) chloride produced from the reaction, you need to use stoichiometry. First, convert the mass of copper (I) oxide to moles. Then, use the mole ratio to find the moles of copper (I) chloride. Finally, convert the moles of copper (I) chloride to grams.

Step-by-step explanation:

To determine the amount of copper (I) chloride produced from the reaction, we need to use stoichiometry. The balanced chemical equation shows that 1 mole of copper (I) oxide reacts with 2 moles of hydrochloric acid to produce 2 moles of copper (I) chloride.

First, we convert the mass of copper (I) oxide to moles by dividing it by the molar mass. Then, using the mole ratio from the balanced equation, we can find the moles of copper (I) chloride produced. Finally, we convert the moles of copper (I) chloride to grams by multiplying it by the molar mass.

Let's calculate it step by step:

1. Calculate the moles of copper (I) oxide: 73.5 g / molar mass of Cu2O
2. Use the mole ratio to find the moles of copper (I) chloride: moles of Cu2O * (2 moles of CuCl / 1 mole of Cu2O)
3. Convert the moles of copper (I) chloride to grams: moles of CuCl * molar mass of CuCl

Answer 2

The balanced equation for the reaction is as follows

Cu₂O + 2HCl ---> 2CuCl + H₂O

Molar ratio of Cu₂O to CuCl is 1:2

mass of Cu₂O reacted - 73.5 g

Number of moles of Cu₂O reacted - 73.5 g / 143 g/mol = 0.51 mol

According to the molar ratio,

when 1 mol of Cu₂O reacts then 2 mol of CuCl is formed

therefore when 0.51 mol of Cu₂O reacts then - 2 x 0.51 mol of CuCl is formed

number of CuCl moles formed - 1.02 mol

mass of CuCl formed - 1.02 mol x 99 g/mol = 101 g

mass of CuCl formed is 101 g