Question

Find the limit. Use l'Hospital's Rule if appropriate. If there is a more elementary method, consider using it. lim x→0+ (2x + 1)cot(x) Incorrect: Your answer is incorrect.

Answer 1

`\displaystyle\lim_(x\to0^+)(2x+1)\cot x=\lim_(x\to0^+)(2x+1)/(\tan x)`

As
`x\to0`, the numerator approaches 1 while
`\tan x\to0`, but since
`x\to0` from above we have
`\tan x>0`, which suggests the limit is
`+\infty`.