Question

Line 1: -2x-2y=4 line 2: x+5y=10 can someone help me ​

Answer 1

(-5, 3)

Explanation:

Solving the system means find the point (x, y) where the 2 lines intersect.

Solve the second equation for x....

x = 10 - 5y (subtract 5y from both sides of equation 2)

Now substitute that value into the first equation...

-2(10 - 5y) - 2y = 4

Solve for y....

-20 + 10y -2y = 4

8y - 20 = 4

8y = 24

y = 3

Plug '3' in for y into either equation and solve for 'x'...

x + 5(3) = 10

x + 15 = 10

x = -5

So (-5, 3) is the point (x, y) where the two lines intersect

Answer 2

x= -5, y=3

uh, you basically just have to multiply x+5y=10 by 2, to cancel out the x or to take it away, then you'll be left with 8y=24. Do the dividing and then it will be y=3. You have to plug it into the equation and so I'll be using the first line I think, -2x-2y=4

so once I plugged in the y I found which is 3 right. It would be -2x-6=4

add 6 to both sides

-2x= 10

I then divided 10 by 2, and then made the answer negative because of the negative left in the 2 and so it would be x=-5