Question

I need help on number 3 please

Answer 1

`\large\boxed{x=10}\\\\\boxed{40^o,\ 50^o,\ 90^o}`

Explanation:

We have the right triangle. The sum of the angles measured in the right triangle is 90 °. Therefore we have the equation:

`4x+(6x-10)=90[/tex<em>]</em></p><p>[tex]4x+6x-10=90` add 10 to both sides

`10x=100` divide both sides by 10

`x=10`

The measure of angles:

Put the value of x to the eqpressions:

`6x-10\to6(10)-10=60-10=50\\\\4x\to4(10)=40`