Question

a jug of drinking water contain 2 1/3 gallons of 5/7 gallons drunk each day how much water was left in The Jug after 2 days​

Answer 1

3/7

Explanation:

1/3 = 7/3

so you have 7/3 and 5/7

find the common denominator and

devide the new denominator by the old denominator

and then multiply that number by the numinator of each fraction

and you should get

49/21 and 15/21

then you multiply the 15/21 by 2 because the questions asks you to determine the amount of water left after 2 days

and you get 30/21

then do 49/21 - 30/21 and you should get 19/21

3 goes into 19 and 21 so you devide 19 and 21 by 3 and you get 3/7