Question

Find the distance between points p (5, 1) and q (3,4)

Answer 1

D=3.60

Explanation:

`D=√((y_2-y_1)^2+(x_2-x_1)^2)`

Where

`(x_1,y_1) = (5,1)`

`(x_2,y_2) = (3,4)`

Replacing these values in the distance formula

`D =√((5-3)^2+(1-4)^2)`

`D =√((2)^2+(-3)^2)`

`D =√(4+9)`

`D =√(13)`

`D =√(13)`

`D= 3.60`