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Which complex number has a distance of radical 17 from the origin on the complex plane?

2+15i
17+i
20-3i
4-i

2 Answers

2 votes

Answer: LAST OPTION

Explanation:

The complex numbers shown have the form:


a+bi

By definition, the distance can the distance of the complex number from the origin on the complex plane can be calculated with the formula shown below:


d=√(a^2+b^2)

Substitute values of each option. Then:

1)
d=√(2^2+15^2)=√(229)

2)
d=√(17^2+1^2)=√(290)

3)
d=√(20^2+(-3)^2)=√(409)

4)
d=√(4^2+(-1)^2)=√(17) (CORRECT OPTION)

User LOLWTFasdasd Asdad
by
8.7k points
7 votes

Answer:

The right choice is (D) 4-i

Explanation:

See the attached image

Which complex number has a distance of radical 17 from the origin on the complex plane-example-1
User Anthony Roy
by
7.2k points

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