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Multiply and simplify (3x+5)(2x^2-3x+2)

User Xaxa
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1 Answer

4 votes

Answer:


\large\boxed{(3x+5)(2x^2-3x+2)=6x^3+x^2-9x+10}

Explanation:


\text{Use FOIL:}\ (a+b)(c+d)=ac+ad+bc+bd\\\\(3x+5)(2x^2-3x+2)\\\\=(3x)(2x^2)+(3x)(-3x)+(3x)(2)+(5)(2x^2)+(5)(-3x)+(5)(2)\\\\=6x^3-9x^2+6x+10x^2-15x+10\\\\\text{combine like terms}\\\\=6x^3+(-9x^2+10x^2)+(6x-15x)+10\\\\=6x^3+x^2-9x+10

User MDave
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