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Multiply (x-4)(x^2+6x-5).

User Altagrace
by
4.9k points

1 Answer

2 votes

Assignment:
\bold{Solve \ Equation: \ \left(x-4\right)\left(x^2+6x-5\right)}

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Answer:
\boxed{\bold{x^3+2x^2-29x+20}}

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Explanation:
\downarrow\downarrow\downarrow

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[ Step One ] Distribute Parenthesis


\bold{xx^2+x\cdot \:6x+x\left(-5\right)+\left(-4\right)x^2+\left(-4\right)\cdot \:6x+\left(-4\right)\left(-5\right)}

[ Step Two ] Apply Addition / Subtraction Rules

Note:
\bold{Addition \ / \ Subtraction \ Rules: \ +\left(-a\right)=-a,\:\:\left(-a\right)\left(-b\right)=ab}


\bold{x^2x+6xx-5x-4x^2-4\cdot \:6x+4\cdot \:5}

[ Step Three ] Simplify
\bold{x^2x+6xx-5x-4x^2-4\cdot \:6x+4\cdot \:5}


\bold{x^3+2x^2-29x+20}

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\bold{\rightarrow Mordancy \leftarrow}

User Gigoland
by
4.8k points