Question

Solve the quadratic equation numerically (using tables of x- and y- values).

x(x + 5) = 0
a.
x = -1 or x = 3
c.
x = -6 or x = 1
b.
x = 0 or x = -5
d.
x =1 or x = -1


Please select the best answer from the choices provided

A
B
C
D

Answer 1

`\text{The solution is }x=0\text{ or }x=-5`

Option b is correct.

Explanation:

Given the quadratic equation

`x(x + 5) = 0`

we have to solve the above equation.

`Equation: \thinspace x(x + 5) = 0`

`x(x + 5) = 0`

By zero product property which states that if ab = 0, then either a = 0 or b = 0, or both a and b are 0.

⇒
`x=0\text{ or }x+5=0`

`x=0\text{ or }x=-5`

Hence, option b is correct.

Answer 2

(x) (x + 5) = 0

Therefore:

• x = 0

• x + 5 = 0
• x = 0 - 5
• x = -5

b. x = 0 or x = -5