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What is the center of a circle with the equation (x-6)^2 +(y+2)^2=9

User GGamba
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1 Answer

4 votes

Answer:

(6,-2)

Explanation:

The center of a circle can be found using the equation
(x-h)^2 + (y-k)^2 = r^2 and is (h,k) from it. Notice h and k are the opposite value as in the equation.

Here in the equation it has - 6 in the h spot. So h = 6. This means k = -2. So the vertex is (6, -2).

User Houcem Berrayana
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