Question

How many grams of H3PO4 are produced when 10.0 moles of water react with an excess of P4O10?

P4O10 +6H2O—>4HPO4

Answer 1

The answer is 653 g

Answer 2

`653.33gH_3PO_4`

Step-by-step explanation:

Hello,

In this case, by considering the given chemical reaction and the molar mass for phosphoric acid and the 4 to 6 relationship between phosphoric acid and water respectively, the required grams are result:

`10.0molH_2O*(4molH_3PO_4)/(6molH_2O) *(98gH_3PO_4)/(1molH_3PO_4) =653.33gH_3PO_4`

Best regards.