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In a parallelogram ABCD, AC ~ BD . Is ABCD a rectangle ?

In a parallelogram ABCD, AC ~ BD . Is ABCD a rectangle ?-example-1
User Brandog
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2 Answers

6 votes

yes it is a rectangle

User Storm Surge
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3 votes

Answer:

Yes

Explanation:

ABCD is a parallelogram

By definition of parallelogram

AB=CD, BC=AD


AC=\cong BD...(given)

AB=AB

Reflexive property

AD=BC (By definition of parallelogram)


\triangleABC
\cong\triangleABD

Reason: SAS postulate


\angle A=\angle B

Reason:CPCT

We know that in parllelogram

Sum of same side interior angle=180 degrees


\angle A+\angle B=180


\angle A+\angle A=180


2\angle A=180


\angle A=(180)/(2)=90^(\circ)


B=\angle 90^(\circ)

We know that

Opposite angles of parallelogram are equal


\angle A=\angle C, \angle B=\angle D


\angle A=\angle B=\angle C=\angle D=90^(\circ)

In rectangle , Opposite sides of rectangle are equal and each angle is of 90 degrees.

Therefore, by definition of rectangle

ABCD is a rectangle.

Hence, proved.

In a parallelogram ABCD, AC ~ BD . Is ABCD a rectangle ?-example-1
User Sam Olesen
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4.9k points