Question

The point-slope from of the equation of the line that passes through (-4, -3) and (12, 1) is y- 1 = 1/4 (x - 12). What is the standard from of the equation from this line?

Answer 1

`\large\boxed{x-4y=8}`

Explanation:

The standard form of an equation of a line:

`Ax+By=C`

We have the equation in point-slope form. Convert:

`y-1=(1)/(4)(x-12)` multiply both sides by 4

`4y-4=x-12` add 4 to both sides

`4y=x-8` subtract x from both sides

`-x+4y=-8` change the signs

`x-4y=8`